Write the formula of Biot-Savart law in vector form. Obtain an expression of magnetic field on the axis of a current-carrying loop. Draw the necessary diagram.
बायो-सावर्ट नियम लिखिए। एक विद्युत धारावाही पाश के अक्ष पर स्थित बिन्दु पर चुम्बकीय क्षेत्र ज्ञात कीजिए। आवश्यक चित्र बनाइए।
🔥 Most repeated · asked 5×Biot savart formula=| dB⃗ | =μ0/4πIdlsinθ/r2

Let us take a circular loop of radius r carrying current I . We have to find the magnetic field at point P which is at axial distance a from the center. By resolving the magnetic field vector of every dl element, we can observe that all the cos component will cancel out whereas the sin component will add up:
So, B=∫dBsinα
B=∫μ0Idlsinθsinα/(4π(√(r2+a2))2)
B=(μ0Isin90∘×sinα)/(4π(r2+a2))∫dl
> From the geometry, sinα=r/(√(r2+a2)) and ∫dl=2πr
B=μ0I/(4π(r2+a2))(r/(√(r2+a2)))2πr; B=μ0I2πr2/(4π(r2+a2)3/2); B=μ0Ir2/(2(r2+a2)3/2); B=μ0Ir2/(2(r2+a2)3/2)
For N turns
B=μ0NIr2/(2(r2+a2)3/2)
If a=0
B=μ0NIR2/(2(r2+a2)3/2); B=μ0NIR2/(2(r2)3/2); B=μ0NIR2/2r3; B=μ0NI/2r
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